yakshp8896
23.12.2020 •
Physics
Un cuerpo se lanza hacia arriba con 50 m/s . ¿A qué altura se encuentra cuando su rapidez es 20 m/s por segunda vez? (g = 10 m/s ^ 2) .
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Ответ:
105 m
Explanation:
Given that the initial velocity of the body, u= 50 m/s in upward direction.
Acceleration due to gravity, g= 10 m / in the downward direction.
Let h be the height of the body when the velocity of the body is 20 m/s.
As the gravitational force acting in the downward direction, so taking it negative as
a= - 10 m/ in the upward direction.
By using the equation of motion ...(i)
Here, u= 50 m/s
v= 20 m/s
s=h
Putting all the values in the equation (i), we have
Hence, the height of the body is 105 m.
Ответ:
1) jumping off a building
2) walking
3) swimming
4) running
5) looking for something