Use the equation 2C4H10+13O2-8CO2+10H2O to find how many moles of oxygen would react with 4 mol C4H10 A. 2
B. 13
C. 25
D. 26

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Ответ:

walmartislife

01.03.2023

Physics

The rocket's altitude at time is

$y(t)=\left(800\dfrac{\rm km}{\rm h}\right)t$

so that after $t=3\,\mathrm{min}$ , it will have traveled

$y=\left(800\dfrac{\rm km}{\rm h}\right)(3\,\mathrm{min})=40\,\mathrm{km}$

The angle of elevation $\theta$ at time is such that

$\tan\theta=\dfrac{y(t)}{13\,\rm km}$

At the moment when $y(t)=30\,\mathrm{km}$ , this angle is

$\tan\theta=\dfrac{30\,\rm km}{13\,\rm km}\implies\theta\approx66.57^\circ$

Differentiating both sides of the equation above gives

$\sec^2\theta\dfrac{\mathrm d\theta}{\mathrm dt}=\dfrac1{13\,\rm km}\dfrac{\mathrm dy(t)}{\mathrm dt}$

and substituting the angle $\theta$ found above, and $\dfrac{\mathrm dy(t)}{\mathrm dt}=800\dfrac{\rm km}{\rm h}$ , we get

$\sec^2\theta66.57^\circ\dfrac{\mathrm d\theta}{\mathrm dt}=\dfrac1{13\,\mathrm km}\left(800\dfrac{\rm km}{\rm h}\right)$

$\implies\boxed{\dfrac{\mathrm d\theta}{\mathrm dt}\approx9.73\dfrac{\rm rad}{\rm h}}$

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Use the equation 2C4H10+13O2-8CO2+10H2O to find how many moles of oxygen would react with 4 mol C4H10 A. 2 B. 13 C. 25 D. 26​