Using Coulomb's Law calculate the electrical force when Q1 = -5 x 10^.9, Q2= 6 x10^ E-9, and the separation distance is 5 m.

The horizontal distance traveled by the projectile is 373.36 m.

Explanation:

Given;

angle of projection; θ = 30⁰

initial velocity of the projectile, u = 65 m/s

The horizontal distance traveled by the projectile or range of the projectile is calculated as;

Therefore, the horizontal distance traveled by the projectile is 373.36 m.