Vis the velocity of a particle moving along the x axis as shown. if x = 2.0 m at
t = 1.0 s, what is the position of the particle at t = 6.0 s?

The magnitude of the force of gravity between two 1.5 kg flower pots if their separation is 1.0 m  is F =  22.05N  

Explanation:

To find the magnitude of the force of gravity between two 1.5 kg flower pots if their separation is 1.0 m

We know that force of gravity is given by the formula,

F =

Where G is the gravitational constant and = 9.8 m/s

m1 and m2 are masses of given objects which is equal to 1.5 kg given

And r is the distance between the objects given = 1 m

So substituting the values in the formula we get,

F =  22.05N