What acceleration will result when a 12 n net force applied to a 3kg object? a 6kg object? i need someone to solve it using an equation and show your work. i really appreciate any i can get.

As per Newton's II law we know that

here for the first case we know that

m = 3 kg

now we will have

now for other case we will have

m = 6 kg

now we have

Total time passed = 2.085 seconds

In the question,

Speed of the train to the left, v = 3 m/s

The slope of the wall (with horizontal) = 12°

Height of the window = 0.83 m

Width of the window = 2.34 m

Now,

The time is needed to be find out for the top edge of the wall to reach the point B (top right) from A (bottom left).

So,

First calculating the time taken by the Wall's top point to reach B in he horizontal is,

Now,

Time taken to reach the top point of the wall up to the height of the window to reach point B is,

Time = Distance traveled by the train in the horizontal until wall reaches B/ Speed of the train

So,

So,

Time taken by the train to cover this distance is,

Therefore, the total time for the point to reach B from A is,

Time = 0.78 + 1.305 = 2.085 seconds

Therefore, Total Time = 2.085 s