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lealaslee858
31.08.2019 •
Physics
What charge appears on each plate of a 10.0 μf parallel plate capacitor, when it is charged to 110 v?
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Ответ:
charge, q = ± 1.1 mC
Given:
Capacitance,![C = 10.0\micro F = 10.0\times 10^{- 6} F](/tpl/images/0214/1008/714e2.png)
Voltage, V = 110 V
Solution:
The charge on the capacitor plates can be calculated by using the definition of capacitance as :
q ∝ V
where
q = charge
V = potential difference or Voltage
Therefore,
q = CV
Now, charge, q :
q =![10.0\times 10^{- 6}\times 110 = 1100\micro C = 1.1 mC](/tpl/images/0214/1008/36bdd.png)
Therefore, the charge on the positive plate is:
q = + 1.1 mC
the charge on the negative plate is:
q = - 1.1 mC
Ответ: