Physics: What electric potential would be measured at a distance of 12cm from a charge of 3.5 x 10-5 c? what would be the potential if the distance were increased to 30 cm? how much work must be done to carry a 3.0 x 10-5 c charge from 12 cm to 30 cm?

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What electric potential would be measured at a distance

Ответ:

warnene17

08.01.2022

Physics

1. $2.19\cdot 10^7 V$

The electric potential produced by a single point charge is

$E=k\frac{q}{r^2}$

where

k is the Coulomb's constant

q is the charge

r is the distance from the charge

In this problem,

$q=3.5\cdot 10^{-5} C\\r=12 cm=0.12 m$

so the electric potential is

$E=(9\cdot 10^9 Nm^2 C^{-2})\frac{(3.5\cdot 10^{-5} C)}{(0.12 m)^2}=2.19\cdot 10^7 V$

2. $3.5\cdot 10^6 V$

Applying the same formula used before

The electric potential produced by a single point charge is

$E=k\frac{q}{r^2}$

where in this case we have

$q=3.5\cdot 10^{-5} C\\r=30 cm=0.30 m$

the electric potential is

$E=(9\cdot 10^9 Nm^2 C^{-2})\frac{(3.5\cdot 10^{-5} C)}{(0.30 m)^2}=3.5\cdot 10^6 V$

3. 644 J

The work done to carry a charge q through a potential difference of $\Delta V$ is given by

$W=q\Delta V$

In this problem, we have

$q=3.5\cdot 10^{-5}C$ is the charge

$\Delta V=V(12 cm)-V(30 cm)=2.19\cdot 10^7 V-3.5\cdot 10^6 V=1.84\cdot 10^7 V$ is the potential difference

Therefore, the work done is

$W=(3.5\cdot 10^{-5} C)(1.84\cdot 10^7 V)=644 J$

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What electric potential would be measured at a distance of 12cm from a charge of 3.5 x 10-5 c? what would be the potential if the distance were increased to 30 cm?
how much work must be done to carry a 3.0 x 10-5 c charge from 12 cm to 30 cm?

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