Physics: What force is needed to pull one microscope slide over another at a speed of 1.00 cm/s, if there is a 0.500-mm-thick layer of 20oC water (η = 1.002 mPa∙s) between them and the contact area is 8.00 cm2?

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What force is needed to pull one microscope slide

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23.01.2022

The force required to pull one microscope is $1.6 \times 10^{-5}$ N

Explanation:

Given:

Area $A = 8 \times 10^{-4}$ $m^{2}$

$\eta = 1.002 \times 10^{-3}$ Pa.s

Thickness $dy = 0.50 \times 10^{-3}$ m

Speed $dv = 1 \times 10^{-2}$ $\frac{m}{s}$

The force needed to pull one microscope is given by,

$F = A\eta \frac{dv}{dy}$

$F = 8 \times 10^{-4} \times 1.002 \times 10^{-3} (\frac{1 \times 10^{-2} }{0.50 \times 10^{-3} } )$

$F = 1.6 \times 10^{-5}$ N

Therefore, the force required to pull one microscope is $1.6 \times 10^{-5}$ N

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