What is the angle between the first-order and second-order bright fringes for a yellow light with a wavelength of 605 nm, and a distance between two slits of 0.0550 mm?

In order to get the answer, use the formula nλ = dsin(θ) where λ is the angle and the wavelength. Work out λ for n =1 and take away from n = 2 as it is asked to find the difference.Then take the tetha in radians as it allows to use the small angle approximation whereas long as θ is small. So Sin(θ) is approximate θ. For n =1, θ = λ/d = 0.011 and n =2, λ/d = 0.022. The difference being 0.011 radians which is 0.630 degrees. 

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