What is the magnitude of the magnetic field created 4.0m away from a 10.0 A current?

The magnitude of the magnetic field created is 5 x 10⁻⁷ T

Explanation:

Given;

magnitude of current, I = 10.0 A

distance of the magnetic field, r = 4.0m

Apply Biot-Savart Law to determine the magnitude of of the magnetic field created;

where;

B is the magnitude of of the magnetic field

μ₀ is constant

I is current

r is the distance of the field

Therefore, the magnitude of the magnetic field created is 5 x 10⁻⁷ T

6.78 X 10³ N/C

Explanation:

Electric field near a charged infinite plate

=  surface charge density / 2ε₀

Field will be perpendicular to the surface of the plate for both the charge density and direction of field will be same so they will add up.

Field due to charge density of +95.0 nC/m2

E₁ = 95 x 10⁻⁹ / 2 ε₀

Field due to charge density of -25.0 nC/m2

E₂ = 25 x 10⁻⁹ /  2ε₀

Total field

E = E₁ + E₂

= 95 x 10⁻⁹ / 2 ε₀ + 25 x 10⁻⁹ /  2ε₀

= 6.78 X 10³ N/C