What is the minimum energy (in MeV) that is required to break a nucleus of 12C (of mass 11.99671 u) into three nuclei of 4He (of mass 4.00151 u each)?
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Ответ:
the minimum energy that needed to break the nucleus is 1.12608 × 10^-12 J
Explanation:
The computation of the minimum energy that needed to break the nucleus is shown below:
The Change in mass is
= 11.99671 - 3 × 4.00151
= 0.00782
The Energy = mc^2
= (0.00782 × 1.6 × 10^{-27}) × (3 × 10^8)^2
= 1.12608 × 10^-12 J
Hence, the minimum energy that needed to break the nucleus is 1.12608 × 10^-12 J
The same is to be considered
Ответ:
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