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maddiemccarter3892
28.02.2020 •
Physics
What is the resistance (in Ω) of thirty-seven 330 Ω resistors connected in series? 12210 Correct: Your answer is correct. Ω (b) What is the resistance (in Ω) of thirty-seven 330 Ω resistors connected in parallel?
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Ответ:
(a) 12210 Ω
(b) 9.92 Ω
Explanation:
From Electricity,
(a)
When resistors are connected in series, the total resistance is the sum of the individual resistance.
From the question,
Rt = R1 + R2 + R3 R37 Equation 1
Where Rt = Total resistance of combined resistance, R1 = resistance of the first resistor, R2 = Resistance of the second resistor and so on up to the 37th resistor.
Note: Since The resistor are identical.
Rt = n(R) Equation 2
Where n = number of resistor, R = resistance of each resistor.
Given: n = 37, R = 330 Ω
Substitute into equation 2
Rt = 37(330)
Rt = 12210 Ω
(b)
For parallel connection,
Rt = R/n Equation 2
Given: R = 330 Ω, n = 37
Substitute into equation 2
Rt = 330/37
Rt = 8.92 Ω
Hence the resistance when connected in parallel = 9.92 Ω
Ответ:
SORRY