What is the speed of a 48-kilogram dog running across
a lawn with 216 joules of kinetic energy?
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Ответ:
3m/s
Explanation:
K.E= (1/2)mv^2
216j= (1/2)48kg • v^2
216J=24kg•v^2
v^2 = (216J)/(24kg)
v^2= 9m^2/s^2
/sqrt{v^2} = /sqrt{9m^2/s^2}
V =3m/s
Ответ:
aaay I'm doing chem too is there a reading cuz they don't give enough info