What is the total capacitance in units of mf, of the two capacitors connected in series, as shown in the diagram, when c1 = 45 mf and c2 = 26 mf?

16.7 mF

Explanation:

The total capacitance of two capacitors connected in series is given by the formula:

in our problem, we have:

C1 = 45 mF is the capacitance of the first capacitor

C2 = 26 mF is the capacitance of the second capacitor

Substituting into the equation, we find:

1000 meters, 200 meters

Explanation:

Given: Vi = 100 m/s and a = -5 m/s^2

From uniformly accelerated equation:  v = Vi + a t

then substitute

0 = 100 -5 t

t = 20 seconds

to go from 100 to 0 at -5m/s^2

d = Vi (20) - (1/2)(5)(20)^2

d = 100 (20) - 2.5(400)

= 2000 - 1000

= 1000 meters to stop, runs 200 meters beyond the end of the runway into the harbor where he strikes a passenger ferry.