What size force does the femur exerts on the kneecap if the tendons are oriented as in the figure and the tension in each tendon is 60 n?
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Ответ:
F(horizontal) = 60 cos 42
= 44.58
Sum of vertical forces = 0
F(vertical) = 60 - 60 sin 42
= 19.85
F = sqrt (Fh² + Fv²)
= sqrt (44.58² + 19.85²)
= 48.8 N
Ответ:
The average time it took the car to travel 0.25 meters was 2.23 seconds
The average time it took the car to travel 0.50 meters was 3.13 seconds
Happy to help :)