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27.06.2019 •
Physics
What value did you calculate for the index of refraction of the glass block in part 2? how does your value compare to the accepted value of 1.53? calculate the percentage error. different materials have distinct indexes of refraction. explain how you might identify a material based on experiments like this one. mention at least one of the difficulties in identifying materials based on their indexes of refraction. trial theta i theta r 1 20 14 2 40 25 3 60 35
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Ответ:
Let's deal with the question one piece at a time:
-- "What value did you calculate for the index of refraction of the glass block in Part 2 ?" . . . . . We were not present for the calculation in Part-2, and have no idea what was going on in that part.
-- "How does your value compare to the accepted value of 1.53 ?" . . . . . Since we were not present for Part-2 and didn't do any calculation, we have nothing to compare with the accepted value of 1.53 .
-- "Calculate the percentage error." . . . . . Since we have no record of a calculation pursuant to Part 2, and are unable to compare it to any other number, we have no way to describe any relationship between them.
-- "Different materials have distinct indexes of refraction. Explain how you might identify a material based on experiments like this one." . . . . . We have no description of the protocol or results of the experiment, so we have no way to explain anything based on it.
-- "Mention at least one of the difficulties in identifying materials based on their indexes of refraction." . . . . . One such drawback is the difficulty of obtaining a sample of the material that is sufficiently, sufficiently homogeneous, and of a useful size and shape, so that a beam of light can be directed through the sample, and accurate representative measurements made of the sample's influence on the light.
Ответ:
C
Explanation:
( I dun know how to explain it but i do know that the answer is C. Saw it in a past paper.)