Physics: When a child fires an air gun that discharges a 0.35 g steel pellet at a velocity of 162 km/h, what is the wavelength in meters of the pellet?

When a child fires an air gun that discharges

melissa3333

17.01.2022

$4.2\cdot 10^{-32} m$

Explanation:

The De Broglie's wavelength of an object is given by:

$\lambda=\frac{h}{mv}$

where

h is the Planck constant

m is the mass of the object

v is the speed of the object

In this problem, we have:

$m=0.35 g=3.5\cdot 10^{-4} kg$ is the mass of the pellet

v=162 km/h=45 m/s is the speed of the pellet

Substituting into the equation, we find the wavelength of the pellet:

$\lambda=\frac{6.63\cdot 10^{-34} Js}{(3.5\cdot 10^{-4}kg)(45 m/s)}=4.2\cdot 10^{-32} m$

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anatomyfl

06.01.2020

Explanation:

The formula for this is

$n_1sin\theta_1=n_2sin\theta_2$ where the index of refraction of air is 1.00. Filling in and solving for n2:

1.00sin(25) = n₂sin(13) and

1.00(.423) = n₂(.225) and

$\frac{1.00(.423)}{.225}=n_2$ so

n_2=1.88 , choice D.

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