liyahheadhigh

22.04.2020 • 

Physics

You are exploring a newly discovered planet. The radius of the planet is 7.30×10⁷m. You suspend a lead weight from the lower end of a light string that is 4.00 m long and has mass 0.0280 kg. You measure that it takes 0.0705 s for a transverse pulse to travel from the lower end to the upper end of the string. On earth, for the same string and lead weight, it takes 0.0390 s for a transverse pulse to travel the length of the string. The weight of the string is small enough that its effect on the tension in the string can be neglected. Assuming that the mass of the planet is distributed with spherical symmetry, what is its mass?

Ответ:

KBH3298

29.09.2020

Physics

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At highest point, velocity = 0, height (potential energy) is max
at lowest point, velocity(Kinetic energy) is max, height (PE) is reduced

total energy at 2 points is equal --- conservation of energy. in the other words, potential energy transform to kinetic energy when decending.

PE reduce = KE increase
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mg(180) - mg(60) = 0.5mv^2 - 0
g(180-60) = 0.5v^2
work from here
... remark ... unit of v is cm/s

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