Physics: You slam on the brakes of your car in a panic and skid a distance X on a straight, level road. If you had been traveling half as fast under the same road conditions, you would have skidded a distance

Explanation:you can do this i bleave in you so get it going...

You slam on the brakes of your car in a panic and

Ответ:

hernandezbrandon059

20.01.2022

Physics

The required skidded distance would be one-forth of the distance skidded if the velocity of the car becomes half.

Explanation:

If ' $v_{0}$ ' be the velocity of the car where the brakes are slammed on and 'a' be the constant deceleration gained by the car before coming to stop after skidding a distance 'X' at time 't' where final velocity ' $v_{t} = 0$ ', then as can be seen from the figure,

$&& v_{t} = v_{0} - a~t\\&or,& 0 = v_{0} - a~t\\&or,& t = \dfrac{v_{0}}{a}$

If from any arbitrarily chosen point 'O', ' $x_{0}$ ' be the distance where the brakes are slammed on and ' $x_{t}$ ' be the distance from the same point 'O' where the car stops, then

$&& x_{t} = \int\limits^t_0 {v_{t}} \, dt\\ = \int\limits^t_0 ({v_{0} - a~t}) \, dt\\ = v_{0}~t - \dfrac{1}{2}~a~t^{2} + x_{0}\\\\&or,& x_{t} - x_{0} = v_{0}~t - \dfrac{1}{2}~a~t^{2}\\&or,& X = v_{0}~\dfrac{v_{0}}{a} - \dfrac{a}{2}(\dfrac{v_{0}}{a})^{2}\\&or,& X = \dfrac{v_{0}^{2}}{a}$

Now if the car would have been moving with a velocity ' $\dfrac{v_{0}}{2}$ ' and would have been skidding a distance 'Y', then from the above equation substituting the velocity we can have

$Y = \dfrac{X}{4}$

So, if the car were moving at half as fast under the same road conditions, it would have skidded by a distance which is one-forth of the present skidded distance.

You slam on the brakes of your car in a panic and skid a distance X on a straight, level road. If yo

0,0(0 оценок)

You slam on the brakes of your car in a panic and skid a distance X on a straight, level road. If you had been traveling half as fast under the same road conditions, you would have skidded a distance

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Physics

Ask an AI advisor a question