Physics: You swing one yo-yo around your head in a horizontal circle. then you swing another yo-yo with twice the mass of the first one, but you don t change the length of the string or the period. how do the tensions in the strings differ?

You swing one yo-yo around your head in a horizontal

Ответ:

brandon2222269

13.03.2022

$F'=2\times F$

Explanation:

You swing one yo-yo around your head in a horizontal circle. The tension acting in the string is equal to the centripetal force. Its formula is given by :

$F=\dfrac{mv^2}{r}$

r is the radius of circular path or the length of the string. It remains constant. If the mass of the yo- yo swing is double such that, m' = 2m

New centripetal force is equal to,

$F'=\dfrac{m'v^2}{r}$

$F'=\dfrac{2mv^2}{r}$

$F'=2\times \dfrac{mv^2}{r}$

$F'=2\times F$

So, the new tension in the strings gets doubled.

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You swing one yo-yo around your head in a horizontal circle. then you swing another yo-yo with twice the mass of the first one, but you don't change the length of the string or the period. how do the tensions in the strings differ?

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