Social Studies: If a radiographer receives an exposure of 0.05 millisievert (msv) at a distance of 1.5 feet from the tube of a portable x-ray unit, what will the exposure be at a distance of 6 feet from the tube?

If a radiographer receives an exposure of 0.05 - id0054354181, genyjoannerubiera

Ответ:

donbright100

13.01.2022

Social Studies

0.003125 msv

Explanation:

I_1 = Initial Exposure = 0.05 msv

I_2 = Final Exposure

D_1 = Initial distance = 1.5 ft

D_2 = Final distance = 6 ft

Exposure is inversely related to the distance squared (inverse square law)

$I\propto \dfrac{1}{D}$

So,

$\dfrac{I_1}{I_2}=\dfrac{D_2^2}{D_1^2}\\\Rightarrow I_2=\dfrac{I_1D_1^2}{D_2^2}\\\Rightarrow I_2=\dfrac{0.05\times 1.5^2}{6^2}\\\Rightarrow I_2=0.003125\ msv$

The exposure at the given distance is 0.003125 msv

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Ответ:

Leftie500

03.05.2020

Social Studies

D is the answer- A Republic

Explanation:

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If a radiographer receives an exposure of 0.05 millisievert (msv) at a distance of 1.5 feet from the tube of a portable x-ray unit, what will the exposure be at a distance of 6 feet from the tube?

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