ethanyayger
29.09.2019 •
Social Studies
The longer an individual is exposed to a strong odor, the less aware of the odor the individual becomes. this phenomenon is known as
Solved
Show answers
More tips
- A Auto and Moto How to Deregister a Car in Moscow?...
- F Food and Cooking How to Cook Julienne? Recipes and Tips...
- D Dating, Love, Relationships 10 Useful Tips on How to Survive a Breakup?...
- F Food and Cooking Apple Cider Vinegar: The Ultimate Health and Beauty Solution...
- C Computers and Internet Е-head: How it Simplifies Life for Users?...
- F Family and Home How to Choose the Best Diapers for Your Baby?...
- F Family and Home Parquet or laminate, which is better?...
- L Leisure and Entertainment How to Properly Wind Fishing Line onto a Reel?...
- L Leisure and Entertainment How to Make a Paper Boat in Simple Steps...
- T Travel and tourism Maldives Adventures: What is the Best Season to Visit the Luxurious Beaches?...
Answers on questions: Social Studies
- H History When does the central region of Chile receive rain? winter spring fall summer...
- M Mathematics Which of the following equations has only one solution? a. x^2-8x+16=0 b. x(x-1)=8 c. x^2=16...
- M Mathematics F (x) = sincx-xcosx/ cosx +xsinx...
- M Mathematics What is the greatest common factor of 40x^3 - 5x^2 - 35x - 20...
- M Mathematics A line includes the points (0,2) and (1, 6) What is the equation of the line in slope intercept form...
Ответ:
The longer an individual is exposed to a strong odor, the less aware of the odor the individual becomes. This phenomenon is known as sensory adaptation.
Sensory adaptation is the ability for your sensory feelings to change and adapt based on their surroundings. One example is wax warmers in the house. I have a wax warmer burning constantly with a scent in 6 places of my house, the first day or so I can smell it but by the second/third day I can't. However, people coming into my house for the first time can smell how strong it is. In this case, my senses adapted to the smell in my house.
Ответ:
Question:
A piston–cylinder device contains 0.85 kg of refrigerant- 134a at -10°C. The piston that is free to move has a mass of 12 kg and a diameter of 25 cm. The local atmospheric pressure is 88 kPa. Now, heat is transferred to refrigerant-134a until the temperature is 15°C. Determine (a) the final pressure, (b) the change in the volume of the cylinder, and (c) the change in the enthalpy of the refrigerant-134a.
a) 90.4 kPa
b) 0.0205 m³
c) 17.4 kJ/kg
Explanation:
Given:
Mass, m = 0.85 kg
a) The final pressure here is equal to the initial pressure. Let's use the formula:
= 90398 Pa
≈ 90.4 KPa
Final pressure = 90.4 kPa
b) Change in volume of the cylinder:
To find the initial and final volume, let's use the values from the A-13 table for refrigerant-134a, at initial values of 90.4 kPa and -10°C and final values of 90.4 kPa and 15°C
v1 = 0.2302m³/kg
h1 = 247.76 kJ/kg
v2 = 0.2544 m³/kg
h2 = 268.2 kJ/kg
Change in volume is calculated as:
Δv = m(v2 - v1)
Δv = 0.85(0.2544 - 0.2302)
= 0.0205 m³
Change in volume = 0.0205 m³
c) Change in enthalpy
Let's use the formula:
Δh = m(h2 - h1)
= 0.85(268.2 - 247.76)
= 17.4 kJ/kg
Change in enthalpy = 17.4 kJ/kg