A population is solely comprised of 181 A2A2 individuals. 11 individuals migrate in and contribute to the mating pool. What is the frequency of A1A2 individuals in the offspring?

The frequency of A1A2 individuals in the offspring is 0.11 Hz.

The number of times a repeated event occurs per unit of time is known as frequency.

It is calculated in Hz.

Given the population is 181 A2A2 individuals

The number of migrated individuals is 11 (A1A2)

So, the total population is 181 + 11 = 192

Now, the genotype frequency is

Now, we will calculate the allele frequency of

The frequency is:

Thus, the frequency is 0.11 Hz.

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The answer is "0.11"

Explanation:

The population is persons with genotype . Persons with  are transferred to the mattress pool of 11, Throughout this new population are also the number of people.

The genotypic frequency alone is the frequencies:

Allelic frequency of

frequency is

The frequency of individual up to two decimal places is

The frequency of allele q around the locus is equal to 0.24

Explanation:

As per the Hardy-Weinberg equation -

Sum of frequency of all alleles around a locus is equal to 1.

Which means

Equation (1)

It is given that

Thus,

Substituting this value in equation (1), we get -

Therefore,  the frequency of allele q around the locus is equal to 0.24