Awoman is heterozygous for blue eyes. if she were to have child with a man who is homozygous recessive for brown eyes, what is the probability of this child having blue eyes? 0% 25% 50% 75%

50%

Explanation:

According to the given information, the woman is heterozygous for blue eyes. It means that the blue eye color is a dominant trait over brown eyes since heterozygous carrier genotypes are present for dominant alleles only.

Let's assume that the allele for blue eye color is "B" and the one for brown eye color is "b". Therefore, the genotype of heterozygous woman would be "Bb" and the genotype of the homozygous recessive male would be "bb".

A cross between Bb x bb gives following phenotype ratio = 50% brown eye : 50% blue eye

There is 50% probability of their child to have blue eye color.

may be option c or b I think but I am not sure