Help plz I giving 100points

Volume of stock 50X TAE buffer required is 4 mL;

Volume of distilled water needed = 196 mL

The researcher will measure 4 mL of the stock 50X TAE solution using a pipette into a 250 mL volumetric flask. The researcher will then add 196 ml of distilled water to make it up to the 200 ml mark.

Explanation:

The following values are given: initial concentration, final concentration and final volume

Initial concentration,C₁ = 50X

Final concentration, C₂ = 1X

Final volume, V₂ = 200 mL

Initial volume, V₁ = ?

Using C₁V₁ =  C₂V₂

V₁ = C₂V₂/C₁

V₁ = 1X * 200 mL/50X

V₁ = 4 mL

Therefore, volume of stock 50X TAE buffer required is 4 mL

Volume of distilled water needed = 200 mL - 4 mL

Volume of distilled water needed = 196 mL

The researcher will measure 4 mL of the stock 50X TAE solution using a pipette into a 250 mL volumetric flask. The researcher will then add 196 ml of distilled water to make it up to the 200 ml mark.