Part C Having correctly established the F2 ratio in Part B, now predict the F2 phenotypic ratio of a "dihybrid" cross involving two independently assorting genes, A and W, for this cross. x The F2 ratio would be: dominant W and dominant A individuals : dominant W and recessive a individuals : recessive w and dominant A individuals : recessive w and recessive a individuals Enter your answer as four numbers separated by colons (example: 9:3:3:1).

The F2 ratio would be: 1:0:0:0 dominant W and dominant A individuals : 1:1:0:0 dominant W and recessive a individuals : 1:1:0:0 recessive w and dominant A individuals : 1:1:0:0 recessive w and recessive a individuals

Explanation:

All the progeny resulting from this cross will be of an identical genotype () since the parent genotype is homozygous dominant being crossed with homozygous recessive. The phenotypic ratio in this case is 1:0:0:0, indicating that all offspring express the dominant trait and are carriers of the recessive trait.

To move substances against a concentration or an electrochemical gradient, the cell must use energy. This energy is harvested from ATP that is generated through cellular metabolism. Active transport mechanisms, collectively called pumps or carrier proteins, work against electrochemical gradients. Hope this helped :)