What does the body build when it needs a gene?
Solved
Show answers
More tips
- S Science and Technology Why is there no gravity on other planets?...
- F Food and Cooking Deflope: What is it and how does it work?...
- B Business and Finance How to Create a Business Plan? Your Ultimate Guide...
- F Food and Cooking Unusually Delicious Shashlik - Follow the Etiquette of Proper Preparation!...
- C Computers and Internet Make Easy Accessible Screenshots on iPad in Just a Few Minutes...
- T Travel and tourism Lost in the Catacombs: What to Do?...
- F Family and Home Protect Your Home or Apartment from Pesky Ants...
- H Health and Medicine How to Treat Styes: Causes, Symptoms, and Home Remedies...
- L Legal consultation What Documents Are Required for a Russian Passport?...
- F Family and Home How to Properly Use a Water Level?...
Answers on questions: Biology
- B Business If firms are more realistic about the services they can provide and at the same time manage customer expectations effectively, they generally can close this gap. Multiple...
- M Mathematics Dewayne says that 60% more than 50 is 80.tationna says that 60% more than 50 is 30.who is right? what mistake did the other person make?...
Ответ:
Bodybuilding, Strength Training, and DNA
Bodybuilders work hard to get chiseled bodies, but many also have a boost from their genetics. One important gene that has been studied and proven to impact strength and muscle size is called ACTN3. ... They are necessary for power sports, like weightlifting and sprinting.
Ответ:
Answer and Explanation:
It is a dihybrid cross, where:
B= black (dominant)
b= brown
S= solid (dominant)
s= spotted
a) The genotype of the parents are:
homozygous black spotted= BBss ⇒ Gametes: Bs, Bs, bS, bS
homozygous brown solid= bbSS ⇒ Gametes: bs, bs, bs, bs
The F1 mice is the resultant progeny from the cross BBss x bbSS. We combine the games of the parents and all combinations are : BbSs. All F1 genotype is BbSs (heterozygous black and solid mice).
b) The testcross is carried out between F1 mice (BbSs) and brown spotted mice (bbss)
BsSs ⇒ Gametes: BS, Bs, bS, bs
bbss ⇒ Gametes: bs, bs, bs, bs
From the gametes, we obtain all the possible combinations:
BSbs = BbSs (black, solid) ⇒ ratio= 1/2 x 1/2= 1/4
Bsbs= Bbss (black, spotted) ⇒ ratio= 1/2 x 1/2= 1/4
bSbs= bbSs (brown solid) ⇒ ratio= 1/2 x 1/2= 1/4
bsbs= bbss (brown spotted) ⇒ ratio= 1/2 x 1/2= 1/4
So, we obtain 1/4 of black solid mice (BbSs), 1/4 of black spotted mice (Bbss), 1/4 of brown solid mice (bbSs) and 1/4 of brown spotted mice (bbss).