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15.12.2020 •
Biology
You now find new cells which contains 200 mM CaCl2 and 15 mM glucose. The cell membrane is permeable to Ca ions, impermeable to Cl- ions, impermeable to Na ions and impermeable to glucose. You transfer these cells into a solution which has 140 mM (NaCl) and 150 mM glucose. What happens to the cells after the solution and cell have come to equilibrium
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Ответ:
The correct answer would be - ions will move from solution 1 to solution 2 so the cell will shrink.
Explanation:
The concentration of CaCl2- = 200mM
CaCl2 dissociates in the three different ions in a solution and each has the same osmolarity
The concentration of glucose = 15 mM
So, the osmolarity of solution 1 would be:
3 × 200 + 15= 615 mM
Similarly, the osmolarity of the second solution would be
The concentration of NaCl = 140 mM
The concentration of glucose = 150 mM
NaCl dissociates in the two different ions in a solution and each has the same osmolarity
140×2+ 150= 430 mM
The solution has more concentration of ions than solution two so the movement of the calcium ion of the CaCl2- would be possible only and therefore, the cell in solution 1 will shrink.
Ответ:
carbon dixoide,sugar,water,oxygen
Explanation: