03.01 CAREER GOALS Directions: Answer the following questions to describe your short-term, mid-term, and long-term career goals. Review the rubric before starting so you know how you will be graded.

What is your career goal? (Summarize your “big picture” career goal in at least two sentences.)

What are the short-term, mid-term, and long-term goals to help you achieve this career goal? (Respond to and describe each goal in two to three sentences)

Short-term goal:

Mid-term goal:

Long-term goal:

IM GIVING BRAINLEAST NO LINKS NO STEALING MY POINTS OR I WILL REPORT YO

For set p, the average is (3 + 4 + 7 + 8 + 8)/5 = 6. the mean absolute deviation can be solved by taking the absolute values of deviations: |3-6| + |4-6| + |7-6| + |8-6| + |8-6| = 3 + 2 + 1 + 2 + 2 = 10, and dividing by 5 to get mean absolute deviation = 2.for set q, the average is (0 + 0 + 1 + 1 + 3 + 7)/6 = 2. the mean absolute deviation can be solved in a similar way: |0-2| + |0-2| + |1-2| + |1-2| + |3-2| + |7-2| = (2 + 2 + 1 + 1 + 1 + 5)/6 = 2.in set q, the range of 1 mean absolute deviation from the mean is 2 +/- 2, which is from 0 to 4. five of the six points (0, 0, 1, 1, and 3) are within this range.in set p, the range of 2 mean absolute deviation from the mean is 6 +/- 2*2 = 6 +/- 4, which is from 2 to 10. all of the five data points (3, 4, 7, 8 and 8) are within this range.the difference between the means of set p minus set q is 6 - 2 = 4. in this particular case, the difference between the means is twice the mean absolute deviation of each set (both of which have a mean absolute deviation of 2). the comparison of the difference between the means versus each group's mean absolute deviation is a way to see whether there is a statistical difference between the two groups. the larger the difference between the means is compared to each group's mean absolute deviation, the larger the probability that the difference between the groups is statistically significant.