The Cash Dividends Payable account at the beginning of year was $90,000 and at the end of year was $10,000. Additional cash dividends declared during the year amounted to $100,000. How would the cash dividend payments be reported on a Statement of Cash Flows?A. Financing activity: $180,000B. Operating activity: $100,000C. Operating activity: $180,000D. Financing activity: $100,000E. Financing activity: $20,000

The distance between the buildings is:

D = 413.3 ft

Step-by-step explanation:

Ok, here we have two triangle rectangles, such that these triangle rectangles share a common vertex which is Dale.

One of the triangles, let's call it triangle A, has the catheti:

Distance between Dale and Building A = d1

Height of Building A = 464 ft

The other triangle (triangle B) has the catheti:

Distance between Dale and Building B = d2

Height of building B = 321ft

We want to find the distance between the buildings, which is equal to d1 + d2.

Then we want to find d1 and d2.

For triangle A:

We know that the angle at the vertex where Dale is standing, is 75°

Then the adjacent cathetus is d1, and the opposite cathetus is the height of building A.

Remember that:

Tan(θ) = (opposite cathetus)/(adjacent cathetus)

Then:

Tan(75°) = (464 ft)/(d1)

d1 = (464 ft)/(Tan(75°)) = 124.3 ft

Now for triangle B, the angle at the vertex where Dale is standing is 48°.

from this vertex, we have d2 as the adjacent cathetus and the height of build B as the opposite cathetus.

Then:

Tan(48°) = 321ft/d2

d2 = (321ft)/(Tan(48°)) = 289ft

Then the distance between the buildings is:

D = d1 + d2 =  124.3 ft +  289ft = 413.3 ft