0.82 moles of water at 25 C absorbs 273 Joules of heat in my kitchen the day my AC was broken. What was the final temperature of the water? Specific heat of water = 4.184 J/g C.
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Formulas if necessary: q = mc (Delta T) where c = specific heat of water= 4.184 J/gC
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Ответ:
Final temperature is 29.42 °C
Explanation:
Mass of water = Number of moles × Molar mass
= 0.82 × (2(1) + 16)
= 0.82 × 18
= 14.76 g
Q=mcΔT. *let's say final temperature is x
273 = 14.76 × 4.184 × ( x - 25 )
273 = 61.76 × ( x - 25 )
273 = 61.76x - 1544
273 + 1544 = 61.76x
1817 = 61.76x
x = 29.42 °C
So the final temperature is 29.42 °C (. ❛ ᴗ ❛.)
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hope this can help