(03.01 lc) an atom has the following electron configuration. 1s22s22p63s23p4 how many valence electrons does this atom have? 2 4 6 12

The correct answer is 6.

Explanation:

Valence electrons is defined as the electrons which are present in the outermost shell of the element.

For the given electronic configuration:  

The valence shell of the given configuration is '3s' and '3p' where n = 3 (highest).

The number of electrons that 3s and 3p sub-shells contain are (2 + 4) = 6

Hence, the number of valence electrons of the given atom is 6.

Empirical formula has a molar mass of 30.01g/mol and molecular formula is C₆H₁₂O₆

Explanation:

Molar mass of a molecule is the sum of the molar mass of each atom. In CH2O we have:

1C = 1*12.01g/mol = 12.01g/mol

2H = 2*1g/mol = 2g/mol

1O = 1*16g/mol = 16g/mol

Empirical formula of CH2O is:

12.01g/mol + 2g/mol + 16g/mol = 30.01g/mol

As the molecular compound has a molar mass of 180.0g/mol the molecular formula is:

180.0g/mol / 30.01g/mol = 6 times the empirical formula. That is: