1. a 5.455-g sample of impure cacl2 is dissolved and treated with excess potassium carbonate solution. the dried caco3 (calcium carbonate) precipitate weighs 4.010-g. calculate the percent by mass of cacl2 in the original mixture.
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Ответ:
The mass percent of calcium chloride in the sample is 81.6 %
Explanation:
To calculate the number of moles, we use the equation:
Given mass of calcium carbonate = 4.010 g
Molar mass of calcium carbonate = 100 g/mol
Putting values in equation 1, we get:
The chemical equation for the reaction of calcium chloride and potassium carbonate follows:
By Stoichiometry of the reaction:
1 mole of calcium carbonate is produced from 1 mole of calcium chloride
So, 0.0401 moles of calcium carbonate will be produced from =
of calcium chloride
Now, calculating the mass of calcium chloride by using equation 1:
Molar mass of calcium chloride = 111 g/mol
Moles of calcium chloride = 0.0401 moles
Putting values in equation 1, we get:
To calculate the mass percentage of calcium chloride in sample, we use the equation:
Mass of sample = 5.455 g
Mass of calcium chloride = 4.451 g
Putting values in above equation, we get:
Hence, the mass percent of calcium chloride in the sample is 81.6 %
Ответ:
Explanation:
hope this helps you to understand :)