1. Calculate the resistivity of the given material whose resistance is 2Ω, length and area of cross section are 15 cm and 25cm² respectedly
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Ответ:
0.033 Ω . m
Explanation:
This is a typical problem that can be solved with the resistivity formula.
ρ = R . A / l
where R is the resistance, A is the area and l, length of the object.
We have all the data in the statement but firstly, we need to convert the area and length in m² and m, respectively because units of ρ are Ω . m
15 cm . 1 m/100 cm = 0.15 m
25 cm² . 1m² / 10000 cm² = 0.0025 m²
We replace → R = 2Ω . (0.0025 m² / 0.15) ⇒ 0.033 Ω . m
A conductive object will be more or less resistant according to the resistivity, which increases with length and decreases with area. Furthermore, resistivity is also conditioned to temperature, where as T ° increases, resistivity increases too.
Ответ:
Titanium, in the jewelry industry, is considered to be a precious metal which is why it is in the ranks of other precious metals such as gold, palladium, platinum, and silver. It has a high economic value because of its hardness and high melting point. However, titanium is not a rare metal, as it is the 9th most abundant metal in the Earth's crust.