1 Determine the amount of heat (q) in joules that is released when 20.0 grams of water is cooled from 85˚C to 5˚C. Remember that the specific heat of water is 4.18 J/g˚C.
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Ответ:
-6688 J
Explanation:
So for this question we have to use equation q=(m)(c)(deltaT)
Mass=20.0 grams
C=4.18 J/g
delta T= final-initial= 5-85=-80
q=(20.0)(4.18)(-80)
q=-6688 J
Ответ:
their elevation is a mile much like Denver 's