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michelle230
27.12.2020 •
Chemistry
1. Magnesium chloride solution reacts with silver nitrate solution to form magnesium nitrate
solution and silver chloride.
Equation: MgCl2 (s) + 2 AgNO3 (aq) → Mg(NO3)2 (aq) + 2 AgCl (s)
Find the mass of silver chloride formed if
(a) 20 cm of 2.5 mol/dm^3 of magnesium chloride solution is used.
(6) 20 cm of 2.5 g/dm^3 of magnesium chloride solution is used.
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Ответ:
a. 1,4332 g
b. 7.54~g
Further explanationGiven
Reaction
MgCl2 (s) + 2 AgNO3 (aq) → Mg(NO3)2 (aq) + 2 AgCl (s)
20 cm of 2.5 mol/dm^3 of MgCl2
20 cm of 2.5 g/dm^3 of MgCl2
Required
the mass of silver chloride - AgCl
Solution
a. mol MgCl2 :
From equation, mol AgCl = 2 x mol MgCl2=2 x 0.05=0.1
mass AgCl(MW=143,32 g/mol)= 0.1 x 143,32=1,4332 g
b. mol MgCl2 (MW=95.211 /mol):
From equation, mol AgCl = 2 x mol MgCl2=2 x 0.0263=0.0526
mass AgCl(MW=143,32 g/mol)= 0.0526 x 143,32=7.54~g
Ответ:
No because of the equation Hydrogen is brought out of it. This will make the equation uneven therefor it is invalid.
Explanation: