2.34 L of N2 is how many molecules of N2 ? (round your answer to three significant
figures)

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Ответ:

hiene

30.09.2020

Chemistry

$\boxed{\text{0.200 mol}}$

Explanation:

The balanced equation is

2CO + O₂ ⇌ 2CO₂

Step 1. Calculate the known concentrations.

$\text{[O$_{2}$]} = \dfrac{\text{0.100 mol}}{\text{3.50 L}} = \text{0.02857 mol/L}\\\\\text{[CO$_{2}$]} = \dfrac{\text{0.400 mol}}{\text{3.50 L}} = \text{0.1143 mol/L}$

Step 2. Calculate the concentration of CO

$K_{\text{eq}} = \dfrac{\text{[CO$_{2}$]$^{2}$}}{\text{[CO]$^{2}$[O$_{2}$]}} = 1.4 \times10^{2}$

$\begin{array}{rcl}\\\\\dfrac{0.1143^{2}}{\text{[CO]$^{2}$} \times 0.02857} & = & 1.4 \times10^{2}\\\\0.01306 & = & 4.000\text{[CO]$^{2}$}\\\\\text{[CO]$^{2}$} & = &\dfrac{0.01306}{4.000}\\\\\text{[CO]$^{2}$} & = & 0.003265\\\text{[CO]} & = & \mathbf{0.05714}\\\end{array}$

3. Calculate the moles of CO

n = 3.50 L × 0.057 14 mol·L⁻¹ = 0.200 mol

$\text{At equilibrium, there are }\boxed{\textbf{0.200 mol}} \text{ of CO in the flask}$

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2.34 L of N2 is how many molecules of N2 ? (round your answer to three significant figures)