alexi25jeep
29.03.2020 •
Chemistry
2. From the following enthalpy changes, calculate the value of AH° for the reaction
CuCl2 (s) + Cu (s) → 2CuCl (s).
Cu (s) + Cl2 (g) → CuCl2 (s)
2Cu (s) + Cl2 (g) 2CuCl(s)
AH° = -206 kJ
AH° = -136 kJ
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Ответ:
Fractional conversion=0.760
Percentage by which the other reactant is in excess=16.56%
extent = 56.23 mol/s
Explanation:
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