2. If the unknown powder was Sodium Bicarbonate (NaHCO3), how many liters of CO2 would you produce if you started with 4.0 grams of Sodium Bicarbonate?

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Ответ:

love5965

24.01.2023

Chemistry

Explanation:

According to the mole concept there are $6.022 \times 10^{23} atoms$ present in 1 mole of a substance.

Mathematically, 1 mole = $6.022 \times 10^{23}$ atoms or molecules

Therefore, number of moles present in 76.8 g of $CO_{2}$ are as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{76.8 g}{44 g/mol}$

= 1.74 mol

As there are two atoms of oxygen are present in a molecule of $CO_{2}$ . Hence, calculate the number of oxygen atoms present in 1.74 mol of $CO_{2}$ as follows.

$2 \times 1.74 mol \times 6.022 \times 10^{23}}atoms /mol$

= $20.95 \times 10^{23}$ atoms

Thus, we can conclude that there are $20.95 \times 10^{23}$ atoms of oxygen are present in 76.8g of $CO_{2}$ .

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