200mL of 12.0M HNO3 is prepared from stock solution of 16.0M HNO3. A,What volume of stock solution of NH3 is used? And b, What volume of water should be added to the stock

a. 150mL of the stock solution was added

b. 50mL of water was added

Explanation:

The solution was diluted from 16.0M to 12.0M, that is:

16.0M / 12.0M = 1.333 times was diluted.

As the volume of the diluted solution is 200mL, the amount of the 16.0M stock solution is:

200mL / 1.333 =

As the volume of the solution is 200mL and 150mL were added of the stock solution, the volume of water is:

200mL - 150mL =

For number 5 the answer is D. Water molecules are split apart. For number 6 the answer is D. Marine plankton. Hope this helps