2k(s) . cl2(g) kl 2kcl(s) write the six possible mole ratios for this equation
im so confused

Given the balanced chemical reaction:

2K(s) + Cl2 (g) > 2 KCl(s)

There are several mole ratios that can be extracted from the equation,

K/KCl = 2/2 = 1
K/Cl2 = 2/1 = 2
Cl2/KCl = 1/2

and then the reciprocal of the three mole ratios, this sums up to 6 mole ratios. 

0.315 atm

Explanation:

PV = nRT

P(96.2) = (1.24)(0.08206)(25 + 273)

P = 0.315 atm