Chemistry: (6 mol)(-393.5 kJ/mol) + (6 mol)(-285.83 kJ/mol)) - (1 mol)(-1,273.02 kJ/mol)= ?kj

(6 mol)(-393.5 kJ/mol) + (6 mol)(-285.83 kJ/mol)) - id6393562858313896694, tedrayoung1

Ответ:

marissalwilliams3

05.08.2021

Chemistry

-2,802.960 kJ

Explanation:

The dimensional equation of the given quantities is presented as follows;

(6 mol) × (-393.5 kJ/mol) + (6 mol) × (-285.83 kJ/mol) - (1 mol) × (-1,273.02 kJ/mol) = ? kJ

The equation, can be written as follows;

$\left (6 \times (-393.5) \, mol \times \dfrac{kJ}{mol} \right ) + \left(6 \times (-285.83) \, mol \times \dfrac{kJ}{mol} \right) - \left (1 \times (-1,273.02) \, mol \times \dfrac{kJ}{mol} \right) = ?$ We note that $mol \times \dfrac{kJ}{mol} \right) = kJ$ , therefore, the above equation becomes;

$\left (6 \times (-393.5) \ kJ\right ) + \left(6 \times (-285.83) \ kJ \right) - \left (1 \, \times (-1,273.02) \ kJ \right) = -2,802.960 kJ$

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(6 mol)(-393.5 kJ/mol) + (6 mol)(-285.83 kJ/mol)) - (1 mol)(-1,273.02 kJ/mol)= ?kj

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