69. a 1 mol sample of gas has a temp of 225k, a vol of 3.3l, and a pressure of 2000 torr
what would be the temperature if the amount of
stant while pressure
drops to 900 torr and volume to 2.75l?
2
co
20
s
c
Solved
Show answers
More tips
- L Leisure and Entertainment What to Give a Girl on March 8?...
- H Health and Medicine Heartburn: Causes and Ways to Get Rid of It...
- H Health and Medicine Simple and Effective: How to Get Rid of Cracked Heels...
- H Health and Medicine Relieving Swelling in Legs: Causes and Ways to Alleviate the Symptom...
- W Work and Career Мерчендайзинг – все, что нужно знать...
- O Other Everything You Need to Know About Kudyabliks...
- F Food and Cooking How to cook crayfish? Everything you need to know...
- F Food and Cooking Homemade kvass: recipe and brewing process...
- H Health and Medicine How to Choose the Right Tanning Cream?...
- S Style and Beauty Secrets of Tying a Pareo: 5 Ways...
Answers on questions: Chemistry
- M Mathematics Un estudiante de baile quiere saber el tipo de clase de baile favorita para los estudiantes de The Dance Academy. Ella encuesta a cada estudiante en su clase de ballet....
- E English Based on the narrarators description of dee in everyday use has this character changed from the way she is during the events described in the story why or why not be...
- P Physics Suppose an objects initial velocity is 10m/s and it’s final velocity is 4 m/s. mass is constant. what can best be concluded about the object based in the work-energy...
Ответ:
T₂ = 84.375 K
Explanation:
Given data:
Initial volume = 3.3 L
Initial pressure = 2000 torr
Initial temperature = 225 K
Final temperature = ?
Final volume = 2.75 L
Final pressure = 900 torr
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
P₁V₁/T₁ = P₂V₂/T₂
T₂ = P₂V₂ T₁ /P₁V₁
T₂ = 900 torr× 2.75 L× 225 K / 2000 torr×3.3 L
T₂ = 556875 K/ 6600
T₂ = 84.375 K
Ответ: