7) Given that 4 NH3 + 5 02- 4 NO + 6 H20, if 3.00 mol NH3 were made to react with excess of oxygen gas, the amount of H20 formed would be:
A) 2.00 mol.
B) 3.00 mol.
C) 4.50 mol.
36.00 mol.
E) none of the above

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Ответ:

jollyjinkings

17.01.2023

Chemistry

The answer is $2.25

I would use this proportion
24 / 3 18/x

18 times 3=54

54 divided by 24=2.25
X=$2.25

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7) Given that 4 NH3 + 5 02- 4 NO + 6 H20, if 3.00 mol NH3 were made to react with excess of oxygen gas, the amount of H20 formed would be: A) 2.00 mol. B) 3.00 mol. C) 4.50 mol. 36.00 mol. E) none of the above