A 1.89 mol sample of gas exerts a pressure of 335 kPa at a temperature of 105C. What is the volume of the container the gas is in?

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Ответ:

flowersthomas1969

12.08.2021

Chemistry

328 ml

Explanation:

We have given final volume =575.2 ml=0.575 L

Final concentration = 0.8012 M

We know that moles of copper(II) nitrate = final volume ×final concentration =0.8012×.0575=0.4606 moles

We have to find initial volume

So initial volume $=\frac{moles\ of \ copper(II)\ nitrate}{initial\ concentration}=\frac{0.4606}{1.403}=0.328L=328ml$

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