A 10.0 % (m/m) solution of potassium chloride, KCl dissolved in water has a density of 1.06 g/mL. What is the molar concentration of this aqueous solution? Molar Mass (KCl) = 74.55 g/mol

1,42M

Explanation:

Molar concentration is given in moles of solute per liter o solution. Assuming you have 100g of solution:

10g KCl × (1mol / 74,55g) = 0,134 moles of KCl

As you have 100g of solution:

100g × (1mL / 1,06g) × (1L / 1000mL) = 0,0943L

That means molar concentration is:

0,134 moles of KCl / 0,0943L = 1,42M

I hope it helps!

Step-by-step explanation:

Given the table:

Month              f(x) = Number of imports    g(x) = Number of exports

January (1)                3                                                1

February (2)             4                                                3

March (3)                  5                                                5

April (4)                     6                                                7

From the table, it is clear that:

Number of imports = number of month + 2

so

also

Number of exports  = 2(number of month) + 1

so

Therefore, number of imports equals the number of month plus one. i.e. , which is a linear function.

If we compare it with slope-intercept form of the line

Then,

slope = m = 1

y-intercept = 2

Also number of exports equals is also a linear function.

i.e.

Here,

slope = m = 2

y-intercept = -1