a chemist dissolves 0.564 moles of manganese (IV) oxide (MnO2) in water, and adds enough water to make 0.510 L of solution. Calculate the molarity of the solution.

The molarity of the solution is 1.1

Explanation:

Molarity is a measure of the concentration of that substance that is defined as the number of moles of solute divided by the volume of the solution.

The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:

Molarity is expressed in units

In this case

Replacing:

Solving:

molarity= 1.1

The molarity of the solution is 1.1

Explanation:

Molar mass:

Molar mass of substance is sum of atomic weight of all the atoms of elements present in it.

HCl

Atomic weight of hydrogen = 1.00 amu

Atomic weight of chlorine = 35.45 amu

Atomic weight of HCl =  1.00+35.45 = 36.45 g/mol

K₂SO4:

Atomic weight of potassium = 39.09× 2 = 78.18 amu

Atomic weight of sulfur = 32.07 amu

Atomic weight of oxygen = 15.99×4 = 63.96 amu

Atomic weight of K₂SO4 =  63.96+32.07+ 78.18 = 174.21 g/mol

Ca(OH)₂:

Atomic weight of calcium = 40.08 amu

Atomic weight of oxygen = 15.99 × 2 amu = 31.98 amu

Atomic weight of hydrogen = 1.00 × 2 = 2.00 amu

Atomic weight of Ca(OH)₂ = 74.06 g/mol

NaOH:

Atomic weight of sodium = 22.99 amu

Atomic weight of oxygen = 15.99 amu

Atomic weight of hydrogen = 1.00 amu

Atomic weight of NaOH = 39.98 g/mol

NO₃:

Atomic weight of nitrogen = 14.01 amu

Atomic weight of oxygen = 15.99×3 = 47.97 amu

Atomic weight of NO₃ = 61.98 g/mol