A hydrogen atom absorbs a photon radiation causing an electron to jump from level one to level two. If the photon/radiation has a wavelength of 5.62 x 10^-3 m to calculate the frequency of the radiation absorbed and the energy change of the electron

1.  

First of all, let's convert the energy of the absorbed photon into Joules:

The energy of the photon can be rewritten as:

where

h is the Planck constant

c is the speed of light

is the wavelength of the photon

Re-arranging the formula, we can solve to find the wavelength of the absorbed photon:

2. 1.24 eV

In this case, when the electron jumps from the n=4 level to the n=3 level, emits a photon with wavelength

So the energy of the emitted photon is given by the formula used previously:

and using

we find

converting into electronvolts,

Explanation:

Correcta.

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