Chemistry: A sample of gas is put into a container with a movable piston that will allow pressure to be maintained. If the sample of gas was initially at 6.50 degrees Celsius and occupied a volume of 11.7 L, what temperature would the sample be if the piston changed the volume to 89.1 L?

A sample of gas is put into a container with a movable

markmeinberg

13.02.2022

2129.72 K

Explanation:

In this experiment, both the amount of gas and the pressure remain constant.

Those are the conditions for Charles' law:

V₁T₂=V₂T₁

For this problem:

V₁ = 11.7 LV₂ = 89.1 LT₁ = 6.50 °CT₂ = ?

We need to calculate T₂, but first we'll convert 6.50 °C to K:

6.50 + 273.16 = 279.66 K

Now we input the data on the equation:

11.7 L * T₂ =89.1 L * 279.66 K

And solve for T₂:

T₂ = 2129.72 K

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29delphina

20.05.2023

Volcanic Activity

Explanation:

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