A solution is made by adding 120 g of citric acid to 210 g of water. What is the percent mass of citric acid in this solution

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Tokkey12

17.03.2022

Chemistry

The concentration of neon in air is 18.14 ppm

Explanation:

We are given:

Mole fraction of neon = $2.6\times 10^{-5}$

This means that $2.6\times 10^{-5}$ moles of neon are present

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of neon = 20.2 g/mol

Moles of neon = $2.6\times 10^{-5}$ moles

Putting values in above equation, we get:

$2.6\times 10^{-5}mol=\frac{\text{Mass of neon}}{20.2g/mol}\\\\\text{Mass of neon}=(2.6\times 10^{-5}mol\times 20.2g/mol)=5.252\times 10^{-4}g$

ppm is the amount of solute (in milligrams) present in kilogram of a solvent. It is also known as parts-per million.

To calculate the ppm of oxygen in sea water, we use the equation:

$\text{ppm}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 10^6$

Both the masses are in grams.

We are given:

Mass of neon = $5.252\times 10^{-4}g$

Mass of solution (air) = 28.96 g

Putting values in above equation, we get:

$\text{ppm of neon in air}=\frac{5.252\times 10^{-4}}{28.96}\times 10^6\\\\\text{ppm of neon in air}=18.14ppm$

Hence, the concentration of neon in air is 18.14 ppm

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